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[DhtmlXQ_adddate]2009-12-08 15:35:00[/DhtmlXQ_adddate]
[DhtmlXQ_editdate]2009-12-08 15:35:00[/DhtmlXQ_editdate]
[DhtmlXQ_title]五七炮进三兵对屏风马21[/DhtmlXQ_title]
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[DhtmlXQ_open]C70 五七炮对屏风马进３卒[/DhtmlXQ_open]
[DhtmlXQ_class]五七炮对屏风马[/DhtmlXQ_class]
[DhtmlXQ_event]新世纪中炮局套路[/DhtmlXQ_event]
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[DhtmlXQ_owner]徐艺萍[/DhtmlXQ_owner]
[DhtmlXQ_oldowner]徐艺萍[/DhtmlXQ_oldowner]
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[DhtmlXQ_comment0]本局节选自《新世纪中炮局套路》之第一章，五七炮进三兵对屏风马之二，书中第109页。人民体育出版社，作者何左峰。[/DhtmlXQ_comment0]
[DhtmlXQ_comment10]红在左马跳边之前先行平炮七路，是当今的又一流行攻法。对此，黑补士以静制动可谓公认的“官着”。黑另有两种应法：[/DhtmlXQ_comment10]
[DhtmlXQ_comment11]红仍不跳左边马，攻法“前卫”。[/DhtmlXQ_comment11]
[DhtmlXQ_comment12]红接走车九平六是不行的，因炮2进7，车六平八，马2进1，车八进二，炮8进4，黑反先。红可走马八进九和车二进六[/DhtmlXQ_comment12]
[DhtmlXQ_comment15]红左马仍按兵不动，对此，黑走法有炮2进7、车1平4、车1平2、马1进1、马2进3和炮8平9[/DhtmlXQ_comment15]
[DhtmlXQ_comment16]第一种变化，黑贪得一马造成己方阵容散乱，得不偿失。[/DhtmlXQ_comment16]
[DhtmlXQ_comment28]黑左翼缺乏右炮掩护，遭受压力而无计解决。红优。[/DhtmlXQ_comment28]
[DhtmlXQ_comment1_21]红虽缺一仕，但有攻势，红优。[/DhtmlXQ_comment1_21]
[DhtmlXQ_comment2_22]黑用右车兑掉红肋车后，黑左车无法投入战斗，还得兑掉。黑这种消极走法不仅造成后手，还要丢中卒。[/DhtmlXQ_comment2_22]
[DhtmlXQ_comment2_33]进入无车棋后，红子力较黑活跃，占优。[/DhtmlXQ_comment2_33]
[DhtmlXQ_comment3_22]本变黑右翼车马炮三大子倾力出击，致左马失去掩护。[/DhtmlXQ_comment3_22]
[DhtmlXQ_comment3_27]黑在红方左翼无所斩获，己方左翼却倍受压抑。现红渡三兵，占优。[/DhtmlXQ_comment3_27]
[DhtmlXQ_comment4_18]黑先走马踏边兵，再行直出右车，战术可取。[/DhtmlXQ_comment4_18]
[DhtmlXQ_comment4_25]黑弃3卒，红跃右马，双方对抢先手。[/DhtmlXQ_comment4_25]
[DhtmlXQ_comment4_31]避兑车可保持对黑子力的牵制。[/DhtmlXQ_comment4_31]
[DhtmlXQ_comment4_34]双方对攻，各有顾忌。[/DhtmlXQ_comment4_34]
[DhtmlXQ_comment5_18]本变黑马踏红七兵，现黑用走过一步的车来兑已走过三步的红车，红右兑车自然对黑有利。[/DhtmlXQ_comment5_18]
[DhtmlXQ_comment5_35]红占先[/DhtmlXQ_comment5_35]
[DhtmlXQ_comment7_26]黑可下[/DhtmlXQ_comment7_26]
[DhtmlXQ_comment8_18]此局面下黑邀兑红过河车的用意是：红若车二平三避兑，黑可炮9退1实施反击。[/DhtmlXQ_comment8_18]
[DhtmlXQ_comment8_33]红炮镇当头后有渡中兵之着，占优。[/DhtmlXQ_comment8_33]
[DhtmlXQ_comment9_22]面对红车六平八捉双威胁，黑若卒3进1，则车六平八，马2进4，炮七进二，炮2平3，兵五进一，红多兵较优[/DhtmlXQ_comment9_22]
[DhtmlXQ_comment10_22]红失子。[/DhtmlXQ_comment10_22]
[DhtmlXQ_comment11_19]红方多兵较优[/DhtmlXQ_comment11_19]
[DhtmlXQ_comment12_19]红势较优[/DhtmlXQ_comment12_19]
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